← Previous Next →
Just want to share my work here. 1. ∫ e^x sin(ax) dx Let I = ∫ e^x sin(ax) dx =^(IBP) e^x sin(ax) − a∫ e^x cos(ax) dx =^(IBP) e^x sin(ax) − a[e^x cos(ax) + a∫ e^x sin(ax) dx] = e^x sin(ax) − ae^x cos(ax) − a^2 I I = e^x sin(ax) − ae^x cos(ax) − a^2 I (a^2 + 1)I = e^x sin(ax) − ae^x cos(ax) I = ((e^x sin(ax))/(a^2 + 1)) − ((ae^x cos(ax))/(a^2 + 1)) + C determinant (((∫ e^x sin(ax) dx = ((e^x sin(ax))/(a^2 + 1)) − ((ae^x cos(ax))/(a^2 + 1)) + C))) 2. ∫ e^x cos(ax) dx Let I = ∫ e^x cos(ax) dx =^(IBP) e^x cos(ax) + a∫ e^x sin(ax) dx =^(IBP) e^x cos(ax) + a[e^x sin(ax) − a∫ e^x cos(ax) dx] = e^x cos(ax) + ae^x sin(ax) − a^2 I I = e^x cos(ax) + ae^x sin(ax) − a^2 I (a^2 + 1)I = e^x cos(ax) + ae^x sin(ax) I = ((e^x cos(ax))/(a^2 + 1)) + ((ae^x sin(ax))/(a^2 + 1)) + C determinant (((∫ e^x cos(ax) dx = ((e^x cos(ax))/(a^2 + 1)) + ((ae^x sin(ax))/(a^2 + 1)) + C))) Note: C is an arbitrary constant Open for corrections.
Integration TTonyCWX  
Unanswered
content
AgniMath
content
Abod
content
TonyCWX
content
0 Answers

No answers yet. Be the first to answer!

Know the answer? Share your knowledge!

📱 Answer on the App