log _(24) 3= a and log _(24) 6 = (b/6) log _(√8) (b−4a)= ? — Tinkutara Math Forum

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log _(24) 3= a and log _(24) 6 = (b/6) log _(√8) (b−4a)= ?

Logarithms Ggolsendro

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oubiji

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Rasheed.Sindhi
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2 Answers

AA5T

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MMathematicalUser2357

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