−−−−−−−−−−−− 𝛀= Σ_(n=0) ^∞ ((1/(3n+2)) −(1/(3n+1)) )= a𝛑 ⇒ a^2 = ? −−−−−−−−−−−− — Tinkutara Math Forum

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−−−−−−−−−−−− 𝛀= Σ_(n=0) ^∞ ((1/(3n+2)) −(1/(3n+1)) )= a𝛑 ⇒ a^2 = ? −−−−−−−−−−−−

Vectors Mmnjuly1970

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