ax^2 +bx+c = 0 x = ((−b±(√(b^2 −4ac)))/(2a)) Example: Find the values of x in the equation x^2 +5x+4 = 0 In order to solve for that, let′s first take a look on what are the values of a, b and c 1x^2 + 5x + 4 = 0 a = 1 ; b = 5 ; c = 4 Now, using the quadratic formula x = ((−5±(√(5^2 −4(1)(4))))/(2(1))) = ((−5±(√(25−16)))/2) = ((−5±3)/2)