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Question Number 145274 by ArielVyny last updated on 03/Jul/21

∫_(∣z∣=1) ((f^− (z))/(z−a))dz

$$\int_{\mid{z}\mid=\mathrm{1}} \frac{\overset{−} {{f}}\left({z}\right)}{{z}−{a}}{dz} \\ $$

Answered by Olaf_Thorendsen last updated on 03/Jul/21

f(a) = (1/(2πi))∮_γ ((f(z))/(z−a)) dz  Ω = ∫_(∣z∣=1) ((f^_ (z))/(z−a)) dz  Ω = 2πif^_ (a)

$${f}\left({a}\right)\:=\:\frac{\mathrm{1}}{\mathrm{2}\pi{i}}\oint_{\gamma} \frac{{f}\left({z}\right)}{{z}−{a}}\:{dz} \\ $$$$\Omega\:=\:\int_{\mid{z}\mid=\mathrm{1}} \frac{\overset{\_} {{f}}\left({z}\right)}{{z}−{a}}\:{dz} \\ $$$$\Omega\:=\:\mathrm{2}\pi{i}\overset{\_} {{f}}\left({a}\right) \\ $$

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