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Question Number 195518 by jubair56 last updated on 04/Aug/23

y=((x^3 −27)/(x^2 +3x+9))  y=((sin^2 x)/(1+cosx))  y=((sinx+cosx)/( (√(1+cos2x))))

$${y}=\frac{{x}^{\mathrm{3}} −\mathrm{27}}{{x}^{\mathrm{2}} +\mathrm{3}{x}+\mathrm{9}} \\ $$$${y}=\frac{{sin}^{\mathrm{2}} {x}}{\mathrm{1}+{cosx}} \\ $$$${y}=\frac{{sinx}+{cosx}}{\:\sqrt{\mathrm{1}+{cos}\mathrm{2}{x}}} \\ $$

Answered by Calculusboy last updated on 04/Aug/23

what are we doing[here

$${what}\:{are}\:{we}\:{doing}\left[{here}\right. \\ $$

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