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Question Number 34746 by candre last updated on 10/May/18
$${y}+\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }=\frac{\mathrm{1}}{{x}}\left({x}\mathrm{ln}\:{x}−\frac{{dy}}{{dx}}+\mathrm{cos}\:{x}\right) \\ $$$${y}=? \\ $$