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Question Number 29347 by sorour87 last updated on 07/Feb/18 | ||
$${y}^{\left(\mathrm{1}\right)} +\left(\frac{\mathrm{2}}{{x}\mathrm{ln}\:{x}}+\frac{\left(\mathrm{1}−\mathrm{4}{x}^{\mathrm{2}} \mathrm{ln}\:{x}\right)}{{x}\left(\mathrm{1}−\mathrm{2}{x}\mathrm{ln}\:{x}\right)}\right){y}=\mathrm{0} \\ $$ | ||