Question Number 69912 by naka3546 last updated on 29/Sep/19 | ||
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$$\sqrt{{xy}}\:\:+\:\:\mathrm{3}\:\:=\:\:{y} \\ $$$${Find}\:\:\frac{{dy}}{{dx}}\:\:. \\ $$ | ||
Answered by MJS last updated on 29/Sep/19 | ||
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$$\frac{{y}}{\mathrm{2}\sqrt{{xy}}}{dx}+\frac{{x}}{\mathrm{2}\sqrt{{xy}}}{dy}={dy} \\ $$$$\frac{{y}}{\mathrm{2}\sqrt{{xy}}}{dx}=\left(\mathrm{1}−\frac{{x}}{\mathrm{2}\sqrt{{xy}}}\right){dy} \\ $$$$\frac{{y}}{\mathrm{2}\sqrt{{xy}}}{dx}=\frac{\mathrm{2}\sqrt{{xy}}−{x}}{\mathrm{2}\sqrt{{xy}}}{dy} \\ $$$$\frac{{dy}}{{dx}}=\frac{{y}}{\mathrm{2}\sqrt{{xy}}−{x}} \\ $$ | ||