Question Number 140525 by mathdanisur last updated on 09/May/21 | ||
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$${x};{y};{z}>\mathrm{0}\:;\:{x}+{y}+{z}=\mathrm{3} \\ $$ $${proof}\:\left({x}^{\mathrm{3}} +\mathrm{2}\right)\left({y}^{\mathrm{3}} +\mathrm{2}\right)\left({z}^{\mathrm{3}} +\mathrm{2}\right)\geqslant\mathrm{3}^{\mathrm{3}} \\ $$ | ||
Answered by mitica last updated on 09/May/21 | ||
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$${jensen} \\ $$ | ||
Answered by mitica last updated on 09/May/21 | ||
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Commented bymathdanisur last updated on 10/May/21 | ||
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$${thanks}\:{sir} \\ $$ | ||