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Question Number 18299 by tawa tawa last updated on 18/Jul/17

x^x^x   = 2,      find  x

$$\mathrm{x}^{\mathrm{x}^{\mathrm{x}} } \:=\:\mathrm{2},\:\:\:\:\:\:\mathrm{find}\:\:\mathrm{x} \\ $$

Commented by mrW1 last updated on 19/Jul/17

no analytic solution  (√2)<x<2

$$\mathrm{no}\:\mathrm{analytic}\:\mathrm{solution} \\ $$$$\sqrt{\mathrm{2}}<\mathrm{x}<\mathrm{2} \\ $$

Commented by tawa tawa last updated on 19/Jul/17

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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