Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 201796 by ajfour last updated on 12/Dec/23

x^4 −15x^2 −30x+104=0  for x∈R     x=2, 4  I want to know the best way to  arrive at these answers (without  guessing). I found one new way.   Shall post later.

$${x}^{\mathrm{4}} −\mathrm{15}{x}^{\mathrm{2}} −\mathrm{30}{x}+\mathrm{104}=\mathrm{0} \\ $$$${for}\:{x}\in\mathbb{R}\:\:\:\:\:{x}=\mathrm{2},\:\mathrm{4} \\ $$$${I}\:{want}\:{to}\:{know}\:{the}\:{best}\:{way}\:{to} \\ $$$${arrive}\:{at}\:{these}\:{answers}\:\left({without}\right. \\ $$$$\left.{guessing}\right).\:{I}\:{found}\:{one}\:{new}\:{way}. \\ $$$$\:{Shall}\:{post}\:{later}. \\ $$

Commented by Frix last updated on 12/Dec/23

Usually it′s the shortest way to “guess”  trying the ±factors of the constant  104=2^3 13  This doesn′t work in the following case:  x^4 −16x^2 −36x+91=0  I′m looking forward to see your solution.

$$\mathrm{Usually}\:\mathrm{it}'\mathrm{s}\:\mathrm{the}\:\mathrm{shortest}\:\mathrm{way}\:\mathrm{to}\:``\mathrm{guess}'' \\ $$$$\mathrm{trying}\:\mathrm{the}\:\pm\mathrm{factors}\:\mathrm{of}\:\mathrm{the}\:\mathrm{constant} \\ $$$$\mathrm{104}=\mathrm{2}^{\mathrm{3}} \mathrm{13} \\ $$$$\mathrm{This}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{work}\:\mathrm{in}\:\mathrm{the}\:\mathrm{following}\:\mathrm{case}: \\ $$$${x}^{\mathrm{4}} −\mathrm{16}{x}^{\mathrm{2}} −\mathrm{36}{x}+\mathrm{91}=\mathrm{0} \\ $$$$\mathrm{I}'\mathrm{m}\:\mathrm{looking}\:\mathrm{forward}\:\mathrm{to}\:\mathrm{see}\:\mathrm{your}\:\mathrm{solution}. \\ $$

Commented by Calculusboy last updated on 15/Dec/23

we can still use another way

$$\boldsymbol{{we}}\:\boldsymbol{{can}}\:{st}\boldsymbol{{ill}}\:\boldsymbol{{use}}\:\boldsymbol{{another}}\:\boldsymbol{{way}} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com