Question Number 117767 by sumit Singh last updated on 13/Oct/20 | ||
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$${x}^{\mathrm{2}} +{y}_{} ^{\mathrm{2}} ={a}^{\mathrm{2}} \sqrt{\mathrm{2}\:} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} ={a}^{\mathrm{2}} \:\:\:\:\:\: \\ $$$$ \\ $$$${what}\:{is}\:{intersection}\:\:{Angle}=?\: \\ $$ | ||
Commented by sumit Singh last updated on 13/Oct/20 | ||
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$$??? \\ $$ | ||
Answered by MJS_new last updated on 13/Oct/20 | ||
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$$\mathrm{these}\:\mathrm{are}\:\mathrm{concentric}\:\mathrm{circles},\:\mathrm{they}\:\mathrm{don}'\mathrm{t} \\ $$$$\mathrm{intersect} \\ $$ | ||