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Question Number 4674 by thachan last updated on 20/Feb/16

x^2 +5x+2=0

$${x}^{\mathrm{2}} +\mathrm{5}{x}+\mathrm{2}=\mathrm{0} \\ $$

Answered by FilupSmith last updated on 20/Feb/16

x=((−b±(√(b^2 −4ac)))/(2a))  x=((−5±(√(25−4(1)(2))))/(2(1)))  x=((−5±(√(17)))/2)

$${x}=\frac{−{b}\pm\sqrt{{b}^{\mathrm{2}} −\mathrm{4}{ac}}}{\mathrm{2}{a}} \\ $$$${x}=\frac{−\mathrm{5}\pm\sqrt{\mathrm{25}−\mathrm{4}\left(\mathrm{1}\right)\left(\mathrm{2}\right)}}{\mathrm{2}\left(\mathrm{1}\right)} \\ $$$${x}=\frac{−\mathrm{5}\pm\sqrt{\mathrm{17}}}{\mathrm{2}} \\ $$

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