Question Number 30032 by Penguin last updated on 15/Feb/18 | ||
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$$\left({x}+\mathrm{1}\right)^{{x}} −{x}^{\left({x}+\mathrm{1}\right)} =\mathrm{1} \\ $$$${x}=? \\ $$ | ||
Commented by Penguin last updated on 15/Feb/18 | ||
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$$\mathrm{x}=\mathrm{2}\:{works} \\ $$$$\mathrm{anything}\:\mathrm{else}? \\ $$ | ||
Commented by Rasheed.Sindhi last updated on 15/Feb/18 | ||
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$${x}=\mathrm{1} \\ $$ | ||
Commented by mrW2 last updated on 15/Feb/18 | ||
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$${x}=\mathrm{0},\:\mathrm{1},\:\mathrm{2} \\ $$ | ||