Question Number 63121 by hovea cw last updated on 29/Jun/19
$${x}^{\mathrm{1}/\mathrm{2}} \:\centerdot\:{x}^{\mathrm{1}/\mathrm{4}} \:\centerdot\:{x}^{\mathrm{1}/\mathrm{8}} \:\centerdot\:{x}^{\mathrm{1}/\mathrm{16}} \:...\:\mathrm{to}\:\infty\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$
Commented by Prithwish sen last updated on 29/Jun/19
$$\mathrm{thank}\:\mathrm{you} \\ $$
Commented by Prithwish sen last updated on 29/Jun/19
$$\mathrm{x}^{\frac{\mathrm{1}}{\mathrm{2}}\:+\frac{\mathrm{1}}{\mathrm{4}}\:+\frac{\mathrm{1}}{\mathrm{8}}\:+\:.....} \\ $$$$=\mathrm{x}^{\frac{\frac{\mathrm{1}}{\mathrm{2}}}{\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}}} \:=\:\mathrm{x} \\ $$$$\mathrm{please}\:\mathrm{check} \\ $$$$ \\ $$
Commented by hovea cw last updated on 29/Jun/19
very correct sir nice one