Question Number 62595 by Pranay last updated on 23/Jun/19
$${what}\:{is}\:\mathrm{2}{sin}^{\mathrm{2}} \theta{cos}^{\mathrm{2}} \theta\:? \\ $$
Commented by ajfour last updated on 23/Jun/19
$${same}\:{as}\:\:\mathrm{2}×\frac{{p}^{\mathrm{2}} }{{h}^{\mathrm{2}} }×\frac{{b}^{\mathrm{2}} }{{h}^{\mathrm{2}} } \\ $$
Answered by MJS last updated on 23/Jun/19
$$\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{1}−\mathrm{cos}\:\mathrm{4}\theta\right) \\ $$