Question Number 216582 by klipto last updated on 11/Feb/25 | ||
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$$ \\ $$$$\mathrm{using}\:\mathrm{first}\:\mathrm{principle}\:\mathrm{solve} \\ $$$$\mathrm{y}=\frac{\mathrm{x}+\mathrm{2}}{\:\sqrt{\mathrm{x}}+\mathrm{2}} \\ $$$$\mathrm{is}\:\mathrm{it}\:\mathrm{possible}\:\mathrm{with}\:\mathrm{first}\:\mathrm{principle} \\ $$ | ||
Commented by Rasheed.Sindhi last updated on 12/Feb/25 | ||
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$$\mathrm{I}\:\mathrm{think}\:\mathrm{he}\:\mathrm{means}\:\mathrm{to}\:\mathrm{find}\:\mathrm{the}\:\mathrm{derivative} \\ $$$$\mathrm{of}\:\mathrm{this}\:\mathrm{function}\:\mathrm{using}\:\mathrm{first}\:\mathrm{principle}. \\ $$ | ||
Commented by Ghisom last updated on 12/Feb/25 | ||
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$$\mathrm{this}\:\mathrm{is}\:\mathrm{a}\:\mathrm{function},\:\mathrm{there}'\mathrm{s}\:\mathrm{nothing}\:\mathrm{to}\:\mathrm{solve} \\ $$ | ||
Commented by klipto last updated on 12/Feb/25 | ||
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$$\boldsymbol{\mathrm{yes}} \\ $$ | ||