Question Number 116355 by Rio Michael last updated on 03/Oct/20
![the speed v of a projectile launched at an angle α to the horizontal is thought to be given by : v = [(1/k)(A + ((sin αt)/g)) + e^(−C/t) ] where k,A, α and C are constants, t is time and g is the gravitational acceleration. determine the base units of A, α and C](Q116355.png)
$$\mathrm{the}\:\mathrm{speed}\:{v}\:\mathrm{of}\:\mathrm{a}\:\mathrm{projectile}\:\mathrm{launched}\:\mathrm{at} \\ $$$$\mathrm{an}\:\mathrm{angle}\:\alpha\:\mathrm{to}\:\mathrm{the}\:\mathrm{horizontal}\:\mathrm{is}\:\mathrm{thought}\:\mathrm{to} \\ $$$$\mathrm{be}\:\mathrm{given}\:\mathrm{by}\:: \\ $$$$\:\:\:\:\:\:\:{v}\:=\:\left[\frac{\mathrm{1}}{{k}}\left({A}\:+\:\frac{\mathrm{sin}\:\alpha{t}}{\mathrm{g}}\right)\:+\:{e}^{−{C}/{t}} \right] \\ $$$$\mathrm{where}\:{k},{A},\:\:\alpha\:\mathrm{and}\:{C}\:\mathrm{are}\:\mathrm{constants},\:{t}\:\mathrm{is}\:\mathrm{time} \\ $$$$\mathrm{and}\:\mathrm{g}\:\mathrm{is}\:\mathrm{the}\:\mathrm{gravitational}\:\mathrm{acceleration}. \\ $$$$\mathrm{determine}\:\mathrm{the}\:\mathrm{base}\:\mathrm{units}\:\mathrm{of}\:{A},\:\alpha\:\mathrm{and}\:{C} \\ $$