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Question Number 136025 by mathmax by abdo last updated on 18/Mar/21
$$\mathrm{sove}\:\mathrm{y}^{''} +\mathrm{2y}−\mathrm{2}\:=\mathrm{xe}^{−\mathrm{x}} \mathrm{sin}\left(\mathrm{2x}\right)\:\:\mathrm{with}\:\mathrm{y}\left(\mathrm{0}\right)=\mathrm{1}\:\mathrm{and}\:\mathrm{y}^{'} \left(\mathrm{0}\right)=−\mathrm{1} \\ $$