Previous in Relation and Functions Next in Relation and Functions
Question Number 125498 by mathmax by abdo last updated on 11/Dec/20
$$\mathrm{sove}\:\left(\mathrm{x}^{\mathrm{2}} −\mathrm{1}\right)\mathrm{y}^{'} −\frac{\mathrm{2x}}{\mathrm{x}^{\mathrm{3}} +\mathrm{1}}\mathrm{y}=\mathrm{x}^{\mathrm{2}} \mathrm{y}^{\mathrm{4}} \\ $$