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Question Number 99819 by mathmax by abdo last updated on 23/Jun/20
$$\mathrm{sove}\:\:\mathrm{sinx}\:\mathrm{y}^{'} \:−\mathrm{cos}\left(\mathrm{2x}\right)\mathrm{y}\:=\mathrm{xe}^{−\mathrm{x}} \\ $$