Question Number 43804 by vuckintv last updated on 15/Sep/18 | ||
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$${solve}\:{for}\:\epsilon \\ $$$$ \\ $$$${s}\left(\mathrm{1}−\alpha\right)=\left(\mathrm{1}−\epsilon\right)\sigma{T}^{\mathrm{4}} \\ $$ | ||
Answered by MJS last updated on 16/Sep/18 | ||
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$$\frac{{s}\left(\mathrm{1}−\alpha\right)}{\sigma{T}^{\mathrm{4}} }=\mathrm{1}−\epsilon \\ $$$$\epsilon=\mathrm{1}−\frac{{s}\left(\mathrm{1}−\alpha\right)}{\sigma{T}^{\mathrm{4}} } \\ $$ | ||