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Question Number 73550 by Rio Michael last updated on 13/Nov/19

solve     87x ≡ 3 (mod 5) and   55x ≡ 35 (mod 75)

$${solve}\: \\ $$$$\:\:\mathrm{87}{x}\:\equiv\:\mathrm{3}\:\left({mod}\:\mathrm{5}\right)\:{and} \\ $$$$\:\mathrm{55}{x}\:\equiv\:\mathrm{35}\:\left({mod}\:\mathrm{75}\right) \\ $$

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