Question Number 116501 by bemath last updated on 04/Oct/20 | ||
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$$\int\:\frac{\mathrm{sin}\:\mathrm{x}−\mathrm{cos}\:\mathrm{x}}{\:\sqrt{\mathrm{sin}\:\mathrm{2x}}}\:\mathrm{dx}\:? \\ $$ | ||
Answered by TANMAY PANACEA last updated on 04/Oct/20 | ||
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$$\frac{{d}}{{dx}}\left({sinx}+{cosx}\right)={cosx}−{sinx} \\ $$$$\int\frac{−{d}\left({sinx}+{cosx}\right)}{\:\sqrt{\mathrm{1}−\mathrm{1}+{sin}\mathrm{2}{x}}} \\ $$$$\int\frac{−{d}\left({sinx}+{cosx}\right)}{\:\sqrt{\left({sinx}+{cosx}\right)^{\mathrm{2}} −\mathrm{1}}} \\ $$$$\int\frac{{dt}}{\:\sqrt{{t}^{\mathrm{2}} −\mathrm{1}}}\:{formula} \\ $$ | ||
Commented by bemath last updated on 04/Oct/20 | ||
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$$=\:−\mathrm{ln}\:\mid\mathrm{t}+\sqrt{\mathrm{t}^{\mathrm{2}} −\mathrm{1}}\:\mid\:+\:\mathrm{c}\: \\ $$$$=\:−\mathrm{ln}\:\mid\mathrm{sin}\:\mathrm{x}+\mathrm{cos}\:\mathrm{x}+\sqrt{\mathrm{sin}\:\mathrm{2x}}\:\mid\:+\:\mathrm{c}\:? \\ $$ | ||
Commented by MJS_new last updated on 04/Oct/20 | ||
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$$\mathrm{yes} \\ $$ | ||