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Question Number 93118 by  M±th+et+s last updated on 11/May/20

sin(x)=a  −1≤a≤1

sin(x)=a1a1

Answered by Rio Michael last updated on 11/May/20

sin (x) = a for −1 ≤a ≤ 1  ⇒ x = πn + (−1)^n  sin^(−1) a   where sin^(−1) a is in radians  or x = 180° n +(−1)^n  sin^(−1) a  where sin^(−1) a is in degrees

sin(x)=afor1a1x=πn+(1)nsin1awheresin1aisinradiansorx=180°n+(1)nsin1awheresin1aisindegrees

Commented by  M±th+et+s last updated on 11/May/20

thank you sir

thankyousir

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