Question Number 96026 by ubaydulla last updated on 29/May/20
$$\mathrm{sin}\:\frac{\mathrm{p}}{\mathrm{x}}=\mathrm{1} \\ $$
Commented by bobhans last updated on 29/May/20
$$\mathrm{sin}\:\left(\frac{\mathrm{p}}{\mathrm{x}}\right)\:=\:\mathrm{sin}\:\left(\frac{\pi}{\mathrm{2}}\right) \\ $$$$\frac{\mathrm{p}}{\mathrm{x}}\:=\:\frac{\pi}{\mathrm{2}}\:+\:\mathrm{2k}\pi\:\Rightarrow\:\frac{\mathrm{x}}{\mathrm{p}}\:=\:\frac{\mathrm{2}}{\pi+\mathrm{4k}\pi}\: \\ $$$$\mathrm{x}\:=\:\frac{\mathrm{2p}}{\pi+\mathrm{4k}\pi} \\ $$