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Question Number 70052 by ahmadshahhimat775@gmail.com last updated on 30/Sep/19
sinA+sinB=nandcosA+cosB=msin(A+B)=?
Answered by $@ty@m123 last updated on 30/Sep/19
sinA+sinB=n⇒2sinA+B2cosA−B2=n....(1)cosA+cosB=m⇒2cosA+B2cosA−B2=m...(2)Dividing(1)by(2),wegettanA+B2=nmWehave,sin(A+B)=2tanA+B21+tan2A+B2=2nm1+n2m2=2mnm2+n2
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