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Question Number 63845 by gunawan last updated on 10/Jul/19
$$\underset{{r}=\mathrm{0}} {\overset{{n}} {\sum}}\:^{{n}} {C}_{{r}} \:\frac{\mathrm{1}+{r}\:\mathrm{log}_{{e}} \:\mathrm{10}}{\left(\mathrm{1}+\:\mathrm{log}_{{e}} \:\mathrm{10}^{{n}} \right)^{{r}} }=... \\ $$
Commented by gunawan last updated on 10/Jul/19
$$\mathrm{answer}\:\mathrm{is}\:\mathrm{0} \\ $$$$\mathrm{please}\:\mathrm{help} \\ $$