Question Number 168480 by amin96 last updated on 11/Apr/22
$$\boldsymbol{\mathrm{n}}^{\mathrm{2}} +\boldsymbol{\mathrm{n}}+\mathrm{109}=\boldsymbol{\mathrm{x}}^{\mathrm{2}} \\ $$$$\boldsymbol{\mathrm{x}}−\boldsymbol{\mathrm{integer}} \\ $$$$\boldsymbol{\mathrm{positive}}\:\boldsymbol{\mathrm{integer}}\:\boldsymbol{\mathrm{solutions}}\:\boldsymbol{\mathrm{n}}=? \\ $$
Commented by Rasheed.Sindhi last updated on 11/Apr/22
$$\mathrm{n}=\mathrm{3},\mathrm{20},\mathrm{35},... \\ $$
Commented by amin96 last updated on 12/Apr/22
$${solution}? \\ $$
Commented by Rasheed.Sindhi last updated on 12/Apr/22
$$ \\ $$
Commented by amin96 last updated on 12/Apr/22
$$? \\ $$
Answered by MrGaster last updated on 21/Dec/24
$${n}=\mathrm{108},\mathrm{35},\mathrm{20},\mathrm{3} \\ $$