Question Number 182077 by cortano1 last updated on 04/Dec/22
$$\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\mathrm{x}\:\mathrm{ln}\:\left(\frac{\sqrt[{\mathrm{4}}]{\mathrm{x}^{\mathrm{2}} +\mathrm{2x}+\mathrm{2}}}{\:\sqrt[{\mathrm{4}}]{\mathrm{16x}^{\mathrm{2}} +\mathrm{2x}}\:−\sqrt{\mathrm{x}}}\:\right)=? \\ $$
Answered by SEKRET last updated on 04/Dec/22
$$\:\:\frac{\mathrm{7}}{\mathrm{16}} \\ $$
Commented by cortano1 last updated on 07/Dec/22
$$\mathrm{no} \\ $$