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Question Number 211745 by Majak last updated on 19/Sep/24

lim_(x→5) (10^2 +5x−20)

$$\underset{{x}\rightarrow\mathrm{5}} {\mathrm{lim}}\left(\mathrm{10}^{\mathrm{2}} +\mathrm{5}{x}−\mathrm{20}\right) \\ $$

Commented by Majak last updated on 19/Sep/24

need help guy

$${need}\:{help}\:{guy} \\ $$

Answered by klipto last updated on 19/Sep/24

=100+25−20=105

$$=\mathrm{100}+\mathrm{25}−\mathrm{20}=\mathrm{105} \\ $$

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