Question Number 197548 by cortano12 last updated on 21/Sep/23 | ||
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$$\:\:\:\:\underset{{x}\rightarrow−\infty} {\mathrm{lim}}\:\left(\frac{\mathrm{4x}−\sqrt{\mathrm{4x}^{\mathrm{2}} +\mathrm{5}}}{\mathrm{2x}−\mathrm{1}}\right)^{\mathrm{bx}} =?\: \\ $$ | ||
Answered by MM42 last updated on 21/Sep/23 | ||
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$${lim}_{{x}\rightarrow−\infty} \:\left(\frac{\mathrm{4}{x}−\mid\mathrm{2}{x}\mid}{\mathrm{2}{x}−\mathrm{1}}\right)^{{bx}} ={lim}_{{x}\rightarrow−\infty} \:\left(\mathrm{3}\right)^{{bx}} \:=\begin{cases}{\:\mathrm{0}\:\:\:\:\:\:\:;\:\:{b}>\mathrm{0}}\\{+\infty\:\:\:;\:\:{b}<\mathrm{0}}\end{cases} \\ $$ | ||
Commented by cortano12 last updated on 21/Sep/23 | ||
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$$\mathrm{wrong} \\ $$ | ||