Question Number 27599 by abdo imad last updated on 10/Jan/18 | ||
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$${let}\:{give}\:{the}\:{equation}\:\:{x}^{\mathrm{6}} −{x}−\mathrm{1}=\mathrm{0}\:\:{by}\:{using}\:{Newton}\:{methodfind} \\ $$$${the}\:{approximate}\:{value}\:{of}\:{the}\:{real}?{root}\:\:{for}\:{this}\:{equation}. \\ $$ | ||