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Question Number 216887 by zetamaths last updated on 23/Feb/25

Π_(k=1) ^n cos((x/2^k ))=Pn(x)  evaluate Pn(x)  and  P_n (x^2 +1)

$$\underset{{k}=\mathrm{1}} {\overset{{n}} {\prod}}{cos}\left(\frac{{x}}{\mathrm{2}^{{k}} }\right)={Pn}\left({x}\right) \\ $$$${evaluate}\:{Pn}\left({x}\right)\:\:{and}\:\:{P}_{{n}} \left({x}^{\mathrm{2}} +\mathrm{1}\right) \\ $$$$ \\ $$$$ \\ $$

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