Question Number 153395 by Rankut last updated on 07/Sep/21
$${given}\:{that}\:\:{f}\left({x}\right)=\mathrm{4}{x}^{\mathrm{3}} −\mathrm{48}{x}.\:{find}\: \\ $$$${the}\:{stationary}\:{point}\:{of}\:{f}\left({x}\right) \\ $$
Answered by puissant last updated on 07/Sep/21
$$\frac{\partial}{\partial{x}}{f}\left({x}\right)=\mathrm{0}\:\Rightarrow\:\mathrm{12}{x}^{\mathrm{2}} −\mathrm{48}=\mathrm{0} \\ $$$$\Rightarrow\:{x}^{\mathrm{2}} =\mathrm{4}\:\Rightarrow\:{x}=\pm\mathrm{2}.. \\ $$