Question Number 111559 by rahuljangir last updated on 04/Sep/20
$${fdx}\sqrt{\mathrm{25}} \\ $$
Commented by Her_Majesty last updated on 04/Sep/20
$${what}\:{do}\:{you}\:{mean}? \\ $$$${fdx}\:{is}\:{a}\:{variable}\:{name}?\:{three}\:{multiplied} \\ $$$${variables}?\:{the}\:{f}\:{stands}\:{for}\:\int?\:{if}\:{so},\:{the} \\ $$$${syntax}\:{is}\:\int{f}\left({x}\right){dx}.\:\int{dx}=\int\mathrm{1}{dx}={x}+{C}\:\Rightarrow \\ $$$$\int{dx}\sqrt{\mathrm{25}}={x}\sqrt{\mathrm{25}}=\mathrm{5}{x}+{C} \\ $$$$ \\ $$
Commented by bemath last updated on 04/Sep/20
$${haha}....{what}\:{the}\:{meaning}\:{f}\:{dx}? \\ $$$${i}\:{know}\:{that}\:\int\:{dx} \\ $$