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Question Number 140828 by jlewis last updated on 13/May/21
$$\mathrm{factorise}\:\mathrm{3k}^{\mathrm{2}} \:+\mathrm{2kh}−\mathrm{8h}^{\mathrm{2}} \\ $$
Answered by liberty last updated on 13/May/21
$$\left(\mathrm{3k}\:\:−\mathrm{4h}\:\:\right)\left(\mathrm{k}+\mathrm{2h}\right) \\ $$
Commented by jlewis last updated on 13/May/21
$${which}\:{method}\:{have}\:{u}\:{used}\:{to}\:{arrive}\:{at}\:{this} \\ $$
Answered by Rasheed.Sindhi last updated on 13/May/21
$$\:\:\:\mathrm{3k}^{\mathrm{2}} \:+\mathrm{2kh}−\mathrm{8h}^{\mathrm{2}} \\ $$$${By}\:{breaking}\:{middle}\:{term} \\ $$$$\:\:=\mathrm{3}{k}^{\mathrm{2}} −\mathrm{4}{kh}+\mathrm{6}{kh}−\mathrm{8}{h}^{\mathrm{2}} \\ $$$$\:={k}\left(\mathrm{3}{k}−\mathrm{4}{h}\right)+\mathrm{2}{h}\left(\mathrm{3}{k}−\mathrm{4}{h}\right) \\ $$$$=\left(\mathrm{3}{k}−\mathrm{4}{h}\right)\left({k}+\mathrm{2}{h}\right) \\ $$
Commented by jlewis last updated on 13/May/21
$${thanks}\:{i}\:{get}\:{it}\:{now} \\ $$