Question Number 123051 by simplyjerico last updated on 22/Nov/20
$${e}^{{y}} =\mathrm{ln}\left(\mathrm{x}^{\mathrm{3}} +\mathrm{3y}\right) \\ $$
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Question Number 123051 by simplyjerico last updated on 22/Nov/20 | ||
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$${e}^{{y}} =\mathrm{ln}\left(\mathrm{x}^{\mathrm{3}} +\mathrm{3y}\right) \\ $$ | ||