Question Number 5479 by keagan j last updated on 15/May/16 | ||
$${cos}\mathrm{180}.{tan}\left(−{x}\right) \\ $$ | ||
Answered by Rasheed Soomro last updated on 15/May/16 | ||
$${cos}\:\mathrm{180}=−\mathrm{1},{tan}\left(−{x}\right)=−{tan}\left({x}\right)\:\left[{tan}\:\:{is}\:{odd}\:{function}\right] \\ $$$$\therefore\:{cos}\mathrm{180}.{tan}\left(−{x}\right)=\left(−\mathrm{1}\right)\left(−{tan}\:{x}\right) \\ $$$$={tan}\:{x} \\ $$ | ||