Question Number 166296 by mathlove last updated on 18/Feb/22 | ||
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$$\left(\mathrm{cos}\:{x}\right)^{\mathrm{2022}} −\left(\mathrm{sin}\:{x}\right)^{\mathrm{2022}} =\mathrm{1} \\ $$$${x}=? \\ $$ | ||
Commented by mkam last updated on 18/Feb/22 | ||
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$$\boldsymbol{{x}}\:=\:\boldsymbol{{n}\pi}\:\forall\:\boldsymbol{{n}}\:\in\:\boldsymbol{{Z}}\: \\ $$ | ||
Commented by mathlove last updated on 19/Feb/22 | ||
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$${How}? \\ $$ | ||