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Question Number 128497 by mathmax by abdo last updated on 07/Jan/21
$$\mathrm{calvulate}\:\mathrm{A}\:=\frac{\mathrm{1}}{\left(\sqrt{\mathrm{3}}−\mathrm{1}\right)^{\mathrm{6}} }+\frac{\mathrm{1}}{\left(\sqrt{\mathrm{3}}+\mathrm{1}\right)^{\mathrm{6}} } \\ $$