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Question Number 204690 by Davidtim last updated on 25/Feb/24

((a^x ÷((b^y ÷(c^z )^(1/r) ))^(1/q) ))^(1/p) =?

$$\sqrt[{{p}}]{{a}^{{x}} \boldsymbol{\div}\sqrt[{{q}}]{{b}^{{y}} \boldsymbol{\div}\sqrt[{{r}}]{{c}^{{z}} }}}=? \\ $$

Answered by A5T last updated on 25/Feb/24

((a^x /(((b^y /c^(z/r) ))^(1/q) )))^(1/p) =(a^(x/p) /(b^(y/q) /c^(z/(rq)) ))=((a^(x/p) c^(z/(rq)) )/b^(y/q) )

$$\left(\frac{{a}^{{x}} }{\left(\frac{{b}^{{y}} }{{c}^{\frac{{z}}{{r}}} }\right)^{\frac{\mathrm{1}}{{q}}} }\right)^{\frac{\mathrm{1}}{{p}}} =\frac{{a}^{\frac{{x}}{{p}}} }{\frac{{b}^{\frac{{y}}{{q}}} }{{c}^{\frac{{z}}{{rq}}} }}=\frac{{a}^{\frac{{x}}{{p}}} {c}^{\frac{{z}}{{rq}}} }{{b}^{\frac{{y}}{{q}}} } \\ $$

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