Question Number 137591 by Ñï= last updated on 04/Apr/21 | ||
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$${a}=\sqrt[{\mathrm{3}}]{\mathrm{4}}+\sqrt[{\mathrm{3}}]{\mathrm{2}}+\sqrt[{\mathrm{3}}]{\mathrm{1}} \\ $$$$\frac{\mathrm{3}}{{a}}+\frac{\mathrm{3}}{{a}^{\mathrm{2}} }+\frac{\mathrm{1}}{{a}^{\mathrm{3}} }=? \\ $$ | ||
Commented by mr W last updated on 05/Apr/21 | ||
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$$=\mathrm{1} \\ $$ | ||