Question and Answers Forum

All Questions   Topic List

VectorQuestion and Answers: Page 10

Question Number 76555    Answers: 1   Comments: 0

Question Number 76554    Answers: 1   Comments: 0

Question Number 76524    Answers: 3   Comments: 0

find vector unit perpendicular to vector a^− =(1,2,3) and b^− =(−1,0,2)

$${find}\:{vector}\:{unit}\:{perpendicular}\: \\ $$$${to}\:{vector}\:\overset{−} {{a}}=\left(\mathrm{1},\mathrm{2},\mathrm{3}\right)\:{and}\:\overset{−} {{b}}=\left(−\mathrm{1},\mathrm{0},\mathrm{2}\right) \\ $$

Question Number 76475    Answers: 1   Comments: 0

Question Number 76088    Answers: 0   Comments: 2

Question Number 76087    Answers: 1   Comments: 0

Question Number 75518    Answers: 1   Comments: 0

Question Number 75260    Answers: 0   Comments: 0

Question Number 74579    Answers: 0   Comments: 0

find the gradient of scalar point function being expressed in term of scalar triple product as u=(a^ ,b^ ,c^ )=a^ .b^ ×c^

$${find}\:{the}\:{gradient}\:{of}\:{scalar}\:{point}\:{function}\:{being}\:{expressed}\:{in}\:{term}\:{of}\:{scalar}\:{triple}\:{product}\:{as}\:{u}=\left(\bar {{a}},\bar {{b}},\bar {{c}}\right)=\bar {{a}}.\bar {{b}}×\bar {{c}} \\ $$

Question Number 73940    Answers: 1   Comments: 0

Question Number 73084    Answers: 1   Comments: 0

Question Number 72832    Answers: 1   Comments: 1

In a parallelogram OABC, OA^⇁ =a^(−⇁) , OC^→ =c^→ , D is a point such that AD^→ :DB^→ =1:2 Express the following in terms of a and c (i)CB^→ (ii)BC^→ (iii)AB^→ (iv) AD^→ (v)OD^→ (vi)DC^→

$${In}\:{a}\:{parallelogram}\:{OABC},\:{O}\overset{\rightharpoondown} {{A}}=\overset{−\rightharpoondown} {{a}}, \\ $$$${O}\overset{\rightarrow} {{C}}=\overset{\rightarrow} {{c}},\:{D}\:{is}\:{a}\:{point}\:{such}\:{that}\:{A}\overset{\rightarrow} {{D}}:{D}\overset{\rightarrow} {{B}}=\mathrm{1}:\mathrm{2} \\ $$$${Express}\:{the}\:{following}\:{in}\:{terms}\:{of}\:{a}\:{and}\:{c} \\ $$$$\left({i}\right){C}\overset{\rightarrow} {{B}}\:\left({ii}\right){B}\overset{\rightarrow} {{C}}\:\left({iii}\right){A}\overset{\rightarrow} {{B}}\:\left({iv}\right)\:{A}\overset{\rightarrow} {{D}}\:\left({v}\right){O}\overset{\rightarrow} {{D}} \\ $$$$\left({vi}\right){D}\overset{\rightarrow} {{C}} \\ $$

Question Number 72773    Answers: 1   Comments: 2

Question Number 71986    Answers: 1   Comments: 0

Question Number 69620    Answers: 0   Comments: 1

Question Number 69585    Answers: 0   Comments: 0

Question Number 68608    Answers: 0   Comments: 0

Question Number 68591    Answers: 0   Comments: 6

Question Number 68315    Answers: 0   Comments: 1

∫(((x^(−3) +2x−4)/x))

$$\int\left(\frac{{x}^{−\mathrm{3}} +\mathrm{2}{x}−\mathrm{4}}{{x}}\right) \\ $$

Question Number 66971    Answers: 0   Comments: 3

∫(dx/(x(√(x^2 +x+1 ))))=? please help

$$\int\frac{\mathrm{dx}}{\mathrm{x}\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{x}+\mathrm{1}\:}}=? \\ $$$$\boldsymbol{\mathrm{p}\mathfrak{l}}\mathrm{ease}\:\mathrm{help} \\ $$

Question Number 64348    Answers: 1   Comments: 0

the vectors a and b are such that ∣a∣ =3 , ∣b∣=5 and a.b=−14 find ∣a−b∣

$${the}\:{vectors}\:\boldsymbol{{a}}\:{and}\:\boldsymbol{{b}}\:{are}\:{such}\:{that}\:\mid\boldsymbol{{a}}\mid\:=\mathrm{3}\:,\:\mid\boldsymbol{{b}}\mid=\mathrm{5}\:{and}\:\boldsymbol{{a}}.\boldsymbol{{b}}=−\mathrm{14} \\ $$$${find}\:\mid\boldsymbol{{a}}−\boldsymbol{{b}}\mid \\ $$

Question Number 64085    Answers: 0   Comments: 0

please just read equation of a line and a plane in vectors. i don′t understand (r−a)×b=0 ??

$${please}\:{just}\:{read}\:{equation}\:{of}\:{a}\:{line}\:{and}\:{a}\:{plane}\:{in}\:{vectors}. \\ $$$${i}\:{don}'{t}\:{understand}\: \\ $$$$\:\:\left(\boldsymbol{{r}}−\boldsymbol{{a}}\right)×\boldsymbol{{b}}=\mathrm{0}\:\:?? \\ $$

Question Number 63427    Answers: 0   Comments: 4

(1) A plane contains the lines ((x+1)/2)=((4−y)/2)=((z−2)/3) and r= (2i+2j + 12k)+t(−i+2j +4k). find (a) the angle between these lines. (b) A cartesian equation of the plane. (2) Given the lines l_1 :((x−10)/3)=((y−1)/1)=((z−9)/4) l_2 :r=(−9j+13k)+μ(i+2j−3k) where μ is a parameter; l_3 :((x+10)/4)=((y+5)/3)=((z+4)/1). a) show that the point (4,−1,1) is common to l_1 and l_2 . Find b) the point of intersection of l_2 and l_3 . c) A vector parametric equation of the plane containing the lines l_2 and l_3 . sir Forkum Michael

$$\left(\mathrm{1}\right)\:{A}\:{plane}\:{contains}\:{the}\:{lines}\:\frac{{x}+\mathrm{1}}{\mathrm{2}}=\frac{\mathrm{4}−{y}}{\mathrm{2}}=\frac{{z}−\mathrm{2}}{\mathrm{3}}\:{and}\: \\ $$$${r}=\:\left(\mathrm{2}{i}+\mathrm{2}{j}\:+\:\mathrm{12}{k}\right)+{t}\left(−{i}+\mathrm{2}{j}\:+\mathrm{4}{k}\right).\:{find} \\ $$$$\left({a}\right)\:{the}\:{angle}\:{between}\:{these}\:{lines}. \\ $$$$\left({b}\right)\:{A}\:{cartesian}\:{equation}\:{of}\:{the}\:{plane}. \\ $$$$\left(\mathrm{2}\right)\:{Given}\:{the}\:{lines}\:\boldsymbol{{l}}_{\mathrm{1}} :\frac{{x}−\mathrm{10}}{\mathrm{3}}=\frac{{y}−\mathrm{1}}{\mathrm{1}}=\frac{{z}−\mathrm{9}}{\mathrm{4}}\:\:\boldsymbol{{l}}_{\mathrm{2}} :{r}=\left(−\mathrm{9}{j}+\mathrm{13}{k}\right)+\mu\left({i}+\mathrm{2}{j}−\mathrm{3}{k}\right) \\ $$$${where}\:\mu\:{is}\:{a}\:{parameter};\:\boldsymbol{{l}}_{\mathrm{3}} :\frac{{x}+\mathrm{10}}{\mathrm{4}}=\frac{{y}+\mathrm{5}}{\mathrm{3}}=\frac{{z}+\mathrm{4}}{\mathrm{1}}. \\ $$$$\left.{a}\right)\:{show}\:{that}\:{the}\:{point}\:\left(\mathrm{4},−\mathrm{1},\mathrm{1}\right)\:{is}\:{common}\:{to}\:\boldsymbol{{l}}_{\mathrm{1}} \:{and}\:\boldsymbol{{l}}_{\mathrm{2}} .\:{Find} \\ $$$$\left.{b}\right)\:{the}\:{point}\:{of}\:{intersection}\:{of}\:\boldsymbol{{l}}_{\mathrm{2}} \:{and}\:\boldsymbol{{l}}_{\mathrm{3}} . \\ $$$$\left.{c}\right)\:{A}\:{vector}\:{parametric}\:{equation}\:{of}\:{the}\:{plane}\:{containing}\:{the} \\ $$$${lines}\:\boldsymbol{{l}}_{\mathrm{2}} \:{and}\:\boldsymbol{{l}}_{\mathrm{3}} . \\ $$$${sir}\:{Forkum}\:{Michael} \\ $$

Question Number 62624    Answers: 2   Comments: 0

Question Number 62622    Answers: 0   Comments: 0

Question Number 62585    Answers: 1   Comments: 0

find the resultant force of a system of three forces O^− P^→ =9N,O^− R^→ =10N and O^− Q^→ 10N acting at point O where angle POR is 135°,angle POQ is 135° and QOR is 90°

$${find}\:{the}\:{resultant}\:{force}\:{of}\:{a}\:{system} \\ $$$${of}\:{three}\:{forces}\:\overset{−} {{O}}\overset{\rightarrow} {{P}}\:=\mathrm{9}{N},\overset{−} {{O}}\overset{\rightarrow} {{R}}\:=\mathrm{10}{N}\:{and}\:\overset{−} {{O}}\overset{\rightarrow} {{Q}}\:\mathrm{10}{N}\: \\ $$$${acting}\:{at}\:{point}\:{O}\:{where}\:{angle}\:{POR}\:{is} \\ $$$$\mathrm{135}°,{angle}\:{POQ}\:{is}\:\mathrm{135}°\:\:{and}\:{QOR}\:{is}\: \\ $$$$\mathrm{90}° \\ $$

  Pg 5      Pg 6      Pg 7      Pg 8      Pg 9      Pg 10      Pg 11      Pg 12      Pg 13      Pg 14   

Terms of Service

Privacy Policy

Contact: [email protected]