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Question Number 41888 by Necxx last updated on 14/Aug/18
$${The}\:{length}\:{of}\:{mercury}\:{column}\:{in} \\ $$$${a}\:{mercury}-{in}-{glass}\:{thermometer} \\ $$$${is}\:\mathrm{4}{cm}\:{at}\:{triple}\:{point}.{What}\:{is}\:{the} \\ $$$${length}\:{of}\:{the}\:{column}\:{when}\:{the} \\ $$$${scale}\:{indicates}\:{temperature}\:{of} \\ $$$$\mathrm{560}{K}. \\ $$
Commented by Necxx last updated on 15/Aug/18
$${please}\:{help} \\ $$
Commented by Necxx last updated on 15/Aug/18
$${please}\:{help} \\ $$
Commented by tanmay.chaudhury50@gmail.com last updated on 15/Aug/18
Commented by tanmay.chaudhury50@gmail.com last updated on 15/Aug/18
$$\frac{{T}_{} }{{T}_{\mathrm{2}} }=\frac{{h}_{\mathrm{1}} }{{h}_{\mathrm{2}} } \\ $$$${h}_{\mathrm{2}} =\frac{{h}_{\mathrm{1}} ×{T}_{\mathrm{2}} }{{T}_{\mathrm{1}} }=\frac{\mathrm{4}×\mathrm{560}}{−\mathrm{38}.\mathrm{83440}+\mathrm{273}}{cm} \\ $$$${h}_{\mathrm{2}} =\frac{\mathrm{4}×\mathrm{560}}{\mathrm{234}.\mathrm{16560}}=\mathrm{9}.\mathrm{57}{cm}....{pls}?{check} \\ $$
Commented by Necxx last updated on 16/Aug/18
$${yes}...{thank}\:{you}\:{sir} \\ $$