Question Number 79000 by gopikrishnan last updated on 22/Jan/20
$${The}\:{differential}\:{equation}\:{of}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{25}\:{is} \\ $$
Commented by jagoll last updated on 22/Jan/20
$$\mathrm{with}\:\mathrm{differential}\:\mathrm{implicit} \\ $$$$\mathrm{2x}+\mathrm{2y}\:\mathrm{y}'\:=\:\mathrm{0} \\ $$$$\mathrm{y}'\:=\:\frac{−\mathrm{2x}}{\mathrm{2y}}\:\Rightarrow\mathrm{y}'\:=\:\frac{−\mathrm{x}}{\sqrt{\mathrm{25}−\mathrm{x}^{\mathrm{2}} }} \\ $$
Commented by gopikrishnan last updated on 22/Jan/20
$${thank}\:{u}\:{sir} \\ $$