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Question Number 192862 by Red1ight last updated on 30/May/23

Solve for x  x^3 −115x+150=0

$$\mathrm{Solve}\:\mathrm{for}\:{x} \\ $$$${x}^{\mathrm{3}} −\mathrm{115}{x}+\mathrm{150}=\mathrm{0} \\ $$

Answered by Frix last updated on 30/May/23

(x−10)(x^2 +10x−15)=0  x_1 =10  x_(2, 3) =−5±2(√(10))

$$\left({x}−\mathrm{10}\right)\left({x}^{\mathrm{2}} +\mathrm{10}{x}−\mathrm{15}\right)=\mathrm{0} \\ $$$${x}_{\mathrm{1}} =\mathrm{10} \\ $$$${x}_{\mathrm{2},\:\mathrm{3}} =−\mathrm{5}\pm\mathrm{2}\sqrt{\mathrm{10}} \\ $$

Commented by Frix last updated on 30/May/23

First try all ±factors of the constant 150

$$\mathrm{First}\:\mathrm{try}\:\mathrm{all}\:\pm\mathrm{factors}\:\mathrm{of}\:\mathrm{the}\:\mathrm{constant}\:\mathrm{150} \\ $$

Commented by Red1ight last updated on 30/May/23

how do you achieve this factorization?

$$\mathrm{how}\:\mathrm{do}\:\mathrm{you}\:\mathrm{achieve}\:\mathrm{this}\:\mathrm{factorization}? \\ $$

Commented by York12 last updated on 30/May/23

intuition

$${intuition} \\ $$

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