Question Number 216664 by Rasheed.Sindhi last updated on 14/Feb/25
$$\mathrm{Solve}\:\mathrm{for}\:\mathrm{non}-\mathrm{negative}\:\mathrm{integers}: \\ $$$$\:\:\:\mathrm{n}^{\mathrm{3}} =\mathrm{3m}\left(\mathrm{m}+\mathrm{2n}+\mathrm{1}\right) \\ $$
Answered by AntonCWX last updated on 15/Feb/25
$${m}={n}=\mathrm{0} \\ $$
Commented by Rasheed.Sindhi last updated on 15/Feb/25
$${process}\:{please}. \\ $$
Commented by AntonCWX08 last updated on 16/Feb/25
$${I}\:{mean}\:{its}\:{obvious}\:{right}? \\ $$$${n}^{\mathrm{3}} =\mathrm{3}{m}\left({n}+\mathrm{2}{m}+\mathrm{1}\right) \\ $$$${Just}\:{multiply}\:{both}\:{by}\:{zero}\:{and}\:{done} \\ $$
Commented by Rasheed.Sindhi last updated on 16/Feb/25
$${Can}\:{you}\:{prove}\:{that}\:{this}\:{is}\:\boldsymbol{{only}} \\ $$$$\boldsymbol{{solution}}? \\ $$