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Question Number 202041 by hardmath last updated on 19/Dec/23

Simplify:   (((√2) − sinα − cosα)/(sinα − cosα))

$$\mathrm{Simplify}:\:\:\:\frac{\sqrt{\mathrm{2}}\:−\:\mathrm{sin}\alpha\:−\:\mathrm{cos}\alpha}{\mathrm{sin}\alpha\:−\:\mathrm{cos}\alpha} \\ $$

Answered by cortano12 last updated on 19/Dec/23

 = (((√2)−(√2) ((1/( (√2))) sin α+(1/( (√2))) cos α))/( (√2) ((1/( (√2))) sin α−(1/( (√2))) cos α)))   = ((1−cos (α−45°))/(sin  (α−45°)))   = csc (α−45°)−cot (α−45°)

$$\:=\:\frac{\sqrt{\mathrm{2}}−\sqrt{\mathrm{2}}\:\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\mathrm{sin}\:\alpha+\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\mathrm{cos}\:\alpha\right)}{\:\sqrt{\mathrm{2}}\:\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\mathrm{sin}\:\alpha−\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\mathrm{cos}\:\alpha\right)} \\ $$$$\:=\:\frac{\mathrm{1}−\mathrm{cos}\:\left(\alpha−\mathrm{45}°\right)}{\mathrm{sin}\:\:\left(\alpha−\mathrm{45}°\right)} \\ $$$$\:=\:\mathrm{csc}\:\left(\alpha−\mathrm{45}°\right)−\mathrm{cot}\:\left(\alpha−\mathrm{45}°\right) \\ $$$$ \\ $$

Commented by hardmath last updated on 20/Dec/23

thankyou Ser

$${thankyou}\:{Ser} \\ $$

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